Distance from Secaucus to Montceau-les-Mines
The shortest distance (air line) between Secaucus and Montceau-les-Mines is 3,772.52 mi (6,071.28 km).
How far is Secaucus from Montceau-les-Mines
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 07:48 (03.05.2025)
Montceau-les-Mines is located in Saône-et-Loire, France within 46° 40' 0.84" N 4° 22' 8.04" E (46.6669, 4.3689) coordinates. The local time in Montceau-les-Mines is 13:48 (03.05.2025)
The calculated flying distance from Montceau-les-Mines to Montceau-les-Mines is 3,772.52 miles which is equal to 6,071.28 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Montceau-les-Mines, Saône-et-Loire, France