Distance from Secaucus to Novy Jicin
The shortest distance (air line) between Secaucus and Novy Jicin is 4,238.28 mi (6,820.85 km).
How far is Secaucus from Novy Jicin
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 00:32 (26.04.2025)
Novy Jicin is located in Moravskoslezský kraj, Czechia within 49° 35' 39.84" N 18° 0' 37.08" E (49.5944, 18.0103) coordinates. The local time in Novy Jicin is 06:32 (26.04.2025)
The calculated flying distance from Novy Jicin to Novy Jicin is 4,238.28 miles which is equal to 6,820.85 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Novy Jicin, Moravskoslezský kraj, Czechia