Distance from Secaucus to Opglabbeek
The shortest distance (air line) between Secaucus and Opglabbeek is 3,703.03 mi (5,959.45 km).
How far is Secaucus from Opglabbeek
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 01:02 (25.02.2025)
Opglabbeek is located in Arr. Maaseik, Belgium within 51° 2' 60" N 5° 34' 59.88" E (51.0500, 5.5833) coordinates. The local time in Opglabbeek is 07:02 (25.02.2025)
The calculated flying distance from Opglabbeek to Opglabbeek is 3,703.03 miles which is equal to 5,959.45 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Opglabbeek, Arr. Maaseik, Belgium