Distance from Secaucus to Sint-Andries
The shortest distance (air line) between Secaucus and Sint-Andries is 3,602.39 mi (5,797.49 km).
How far is Secaucus from Sint-Andries
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 10:37 (24.04.2025)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 16:37 (24.04.2025)
The calculated flying distance from Sint-Andries to Sint-Andries is 3,602.39 miles which is equal to 5,797.49 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Sint-Andries, Arr. Brugge, Belgium