Distance from Secaucus to Steenokkerzeel
The shortest distance (air line) between Secaucus and Steenokkerzeel is 3,663.06 mi (5,895.12 km).
How far is Secaucus from Steenokkerzeel
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 05:25 (25.02.2025)
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 11:25 (25.02.2025)
The calculated flying distance from Steenokkerzeel to Steenokkerzeel is 3,663.06 miles which is equal to 5,895.12 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium