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      Distance from Secaucus to Voisins-le-Bretonneux

      The shortest distance (air line) between Secaucus and Voisins-le-Bretonneux is 3,616.63 mi (5,820.40 km).

      How far is Secaucus from Voisins-le-Bretonneux

      Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 23:09 (02.06.2025)

      Voisins-le-Bretonneux is located in Yvelines, France within 48° 45' 29.88" N 2° 3' 2.88" E (48.7583, 2.0508) coordinates. The local time in Voisins-le-Bretonneux is 05:09 (03.06.2025)

      The calculated flying distance from Voisins-le-Bretonneux to Voisins-le-Bretonneux is 3,616.63 miles which is equal to 5,820.40 km.

      Secaucus, New Jersey, United States

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      Voisins-le-Bretonneux, Yvelines, France

      Related Distances to Voisins-le-Bretonneux