Distance from Secaucus to Wommelgem
The shortest distance (air line) between Secaucus and Wommelgem is 3,656.25 mi (5,884.16 km).
How far is Secaucus from Wommelgem
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 10:47 (22.06.2025)
Wommelgem is located in Arr. Antwerpen, Belgium within 51° 12' 0" N 4° 31' 0.12" E (51.2000, 4.5167) coordinates. The local time in Wommelgem is 16:47 (22.06.2025)
The calculated flying distance from Wommelgem to Wommelgem is 3,656.25 miles which is equal to 5,884.16 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Wommelgem, Arr. Antwerpen, Belgium