Distance from Sedro-Woolley to Aleksandrow Kujawski
The shortest distance (air line) between Sedro-Woolley and Aleksandrow Kujawski is 5,066.53 mi (8,153.79 km).
How far is Sedro-Woolley from Aleksandrow Kujawski
Sedro-Woolley is located in Washington, United States within 48° 30' 40.32" N -123° 46' 4.44" W (48.5112, -122.2321) coordinates. The local time in Sedro-Woolley is 22:34 (22.05.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 07:34 (23.05.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 5,066.53 miles which is equal to 8,153.79 km.
Sedro-Woolley, Washington, United States
Related Distances from Sedro-Woolley
Aleksandrow Kujawski, Włocławski, Poland