Distance from Seguin to Boortmeerbeek
The shortest distance (air line) between Seguin and Boortmeerbeek is 5,157.31 mi (8,299.90 km).
How far is Seguin from Boortmeerbeek
Seguin is located in Texas, United States within 29° 35' 20.76" N -98° 1' 56.64" W (29.5891, -97.9676) coordinates. The local time in Seguin is 07:41 (14.04.2025)
Boortmeerbeek is located in Arr. Leuven, Belgium within 50° 58' 59.88" N 4° 34' 0.12" E (50.9833, 4.5667) coordinates. The local time in Boortmeerbeek is 14:41 (14.04.2025)
The calculated flying distance from Boortmeerbeek to Boortmeerbeek is 5,157.31 miles which is equal to 8,299.90 km.
Related Distances from Seguin
Boortmeerbeek, Arr. Leuven, Belgium