Distance from Selnica ob Dravi to Montechiarugolo
The shortest distance (air line) between Selnica ob Dravi and Montechiarugolo is 276.62 mi (445.17 km).
How far is Selnica ob Dravi from Montechiarugolo
Selnica ob Dravi is located in Podravska, Slovenia within 46° 33' 5.04" N 15° 29' 40.92" E (46.5514, 15.4947) coordinates. The local time in Selnica ob Dravi is 02:19 (22.05.2025)
Montechiarugolo is located in Parma, Italy within 44° 41' 36.24" N 10° 25' 20.64" E (44.6934, 10.4224) coordinates. The local time in Montechiarugolo is 02:19 (22.05.2025)
The calculated flying distance from Montechiarugolo to Montechiarugolo is 276.62 miles which is equal to 445.17 km.
Selnica ob Dravi, Podravska, Slovenia