Distance from Seminole to Janow Lubelski
The shortest distance (air line) between Seminole and Janow Lubelski is 5,361.70 mi (8,628.82 km).
How far is Seminole from Janow Lubelski
Seminole is located in Florida, United States within 27° 50' 36.6" N -83° 12' 57.6" W (27.8435, -82.7840) coordinates. The local time in Seminole is 05:58 (03.06.2025)
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 11:58 (03.06.2025)
The calculated flying distance from Janow Lubelski to Janow Lubelski is 5,361.70 miles which is equal to 8,628.82 km.
Seminole, Florida, United States
Related Distances from Seminole
Janow Lubelski, Puławski, Poland