Distance from Seminole to Lovendegem
The shortest distance (air line) between Seminole and Lovendegem is 4,595.76 mi (7,396.16 km).
How far is Seminole from Lovendegem
Seminole is located in Florida, United States within 27° 50' 36.6" N -83° 12' 57.6" W (27.8435, -82.7840) coordinates. The local time in Seminole is 07:44 (07.11.2024)
Lovendegem is located in Arr. Gent, Belgium within 51° 6' 0" N 3° 36' 0" E (51.1000, 3.6000) coordinates. The local time in Lovendegem is 13:44 (07.11.2024)
The calculated flying distance from Lovendegem to Lovendegem is 4,595.76 miles which is equal to 7,396.16 km.
Seminole, Florida, United States
Related Distances from Seminole
Lovendegem, Arr. Gent, Belgium