Distance from Seminole to Waddinxveen
The shortest distance (air line) between Seminole and Waddinxveen is 4,621.03 mi (7,436.82 km).
How far is Seminole from Waddinxveen
Seminole is located in Florida, United States within 27° 50' 36.6" N -83° 12' 57.6" W (27.8435, -82.7840) coordinates. The local time in Seminole is 18:01 (28.05.2025)
Waddinxveen is located in Oost-Zuid-Holland, Netherlands within 52° 2' 60" N 4° 39' 0" E (52.0500, 4.6500) coordinates. The local time in Waddinxveen is 00:01 (29.05.2025)
The calculated flying distance from Waddinxveen to Waddinxveen is 4,621.03 miles which is equal to 7,436.82 km.
Seminole, Florida, United States
Related Distances from Seminole
Waddinxveen, Oost-Zuid-Holland, Netherlands