Distance from Sendenhorst to Aubergenville
The shortest distance (air line) between Sendenhorst and Aubergenville is 329.89 mi (530.91 km).
How far is Sendenhorst from Aubergenville
Sendenhorst is located in Warendorf, Germany within 51° 50' 38.04" N 7° 49' 40.08" E (51.8439, 7.8278) coordinates. The local time in Sendenhorst is 19:38 (03.06.2025)
Aubergenville is located in Yvelines, France within 48° 57' 29.88" N 1° 51' 18" E (48.9583, 1.8550) coordinates. The local time in Aubergenville is 19:38 (03.06.2025)
The calculated flying distance from Aubergenville to Aubergenville is 329.89 miles which is equal to 530.91 km.
Sendenhorst, Warendorf, Germany
Related Distances from Sendenhorst
Aubergenville, Yvelines, France