Distance from Sendenhorst to Begijnendijk
The shortest distance (air line) between Sendenhorst and Begijnendijk is 142.92 mi (230.02 km).
How far is Sendenhorst from Begijnendijk
Sendenhorst is located in Warendorf, Germany within 51° 50' 38.04" N 7° 49' 40.08" E (51.8439, 7.8278) coordinates. The local time in Sendenhorst is 10:40 (15.11.2024)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 10:40 (15.11.2024)
The calculated flying distance from Begijnendijk to Begijnendijk is 142.92 miles which is equal to 230.02 km.
Sendenhorst, Warendorf, Germany
Related Distances from Sendenhorst
Begijnendijk, Arr. Leuven, Belgium