Distance from Sendenhorst to Levallois-Perret
The shortest distance (air line) between Sendenhorst and Levallois-Perret is 317.86 mi (511.55 km).
How far is Sendenhorst from Levallois-Perret
Sendenhorst is located in Warendorf, Germany within 51° 50' 38.04" N 7° 49' 40.08" E (51.8439, 7.8278) coordinates. The local time in Sendenhorst is 16:52 (12.05.2025)
Levallois-Perret is located in Hauts-de-Seine, France within 48° 53' 42" N 2° 17' 13.92" E (48.8950, 2.2872) coordinates. The local time in Levallois-Perret is 16:52 (12.05.2025)
The calculated flying distance from Levallois-Perret to Levallois-Perret is 317.86 miles which is equal to 511.55 km.
Sendenhorst, Warendorf, Germany
Related Distances from Sendenhorst
Levallois-Perret, Hauts-de-Seine, France