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      Distance from Sendenhorst to Saint-Andre-les-Vergers

      The shortest distance (air line) between Sendenhorst and Saint-Andre-les-Vergers is 297.68 mi (479.06 km).

      How far is Sendenhorst from Saint-Andre-les-Vergers

      Sendenhorst is located in Warendorf, Germany within 51° 50' 38.04" N 7° 49' 40.08" E (51.8439, 7.8278) coordinates. The local time in Sendenhorst is 06:33 (04.06.2025)

      Saint-Andre-les-Vergers is located in Aube, France within 48° 16' 46.92" N 4° 3' 14.04" E (48.2797, 4.0539) coordinates. The local time in Saint-Andre-les-Vergers is 06:33 (04.06.2025)

      The calculated flying distance from Saint-Andre-les-Vergers to Saint-Andre-les-Vergers is 297.68 miles which is equal to 479.06 km.

      Sendenhorst, Warendorf, Germany

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      Saint-Andre-les-Vergers, Aube, France

      Related Distances to Saint-Andre-les-Vergers