Distance from Sendenhorst to Sainte-Savine
The shortest distance (air line) between Sendenhorst and Sainte-Savine is 296.93 mi (477.86 km).
How far is Sendenhorst from Sainte-Savine
Sendenhorst is located in Warendorf, Germany within 51° 50' 38.04" N 7° 49' 40.08" E (51.8439, 7.8278) coordinates. The local time in Sendenhorst is 07:49 (07.06.2025)
Sainte-Savine is located in Aube, France within 48° 17' 40.92" N 4° 2' 56.04" E (48.2947, 4.0489) coordinates. The local time in Sainte-Savine is 07:49 (07.06.2025)
The calculated flying distance from Sainte-Savine to Sainte-Savine is 296.93 miles which is equal to 477.86 km.
Sendenhorst, Warendorf, Germany