Distance from Seven Hills to Boortmeerbeek
The shortest distance (air line) between Seven Hills and Boortmeerbeek is 3,938.56 mi (6,338.49 km).
How far is Seven Hills from Boortmeerbeek
Seven Hills is located in Ohio, United States within 41° 22' 49.08" N -82° 19' 35.04" W (41.3803, -81.6736) coordinates. The local time in Seven Hills is 18:03 (02.04.2025)
Boortmeerbeek is located in Arr. Leuven, Belgium within 50° 58' 59.88" N 4° 34' 0.12" E (50.9833, 4.5667) coordinates. The local time in Boortmeerbeek is 00:03 (03.04.2025)
The calculated flying distance from Boortmeerbeek to Boortmeerbeek is 3,938.56 miles which is equal to 6,338.49 km.
Seven Hills, Ohio, United States
Related Distances from Seven Hills
Boortmeerbeek, Arr. Leuven, Belgium