Distance from Seven Hills to Buggenhout
The shortest distance (air line) between Seven Hills and Buggenhout is 3,923.79 mi (6,314.73 km).
How far is Seven Hills from Buggenhout
Seven Hills is located in Ohio, United States within 41° 22' 49.08" N -82° 19' 35.04" W (41.3803, -81.6736) coordinates. The local time in Seven Hills is 17:06 (02.04.2025)
Buggenhout is located in Arr. Dendermonde, Belgium within 51° 0' 0" N 4° 12' 0" E (51.0000, 4.2000) coordinates. The local time in Buggenhout is 23:06 (02.04.2025)
The calculated flying distance from Buggenhout to Buggenhout is 3,923.79 miles which is equal to 6,314.73 km.
Seven Hills, Ohio, United States
Related Distances from Seven Hills
Buggenhout, Arr. Dendermonde, Belgium