Distance from Seven Hills to Kalmthout
The shortest distance (air line) between Seven Hills and Kalmthout is 3,922.29 mi (6,312.32 km).
How far is Seven Hills from Kalmthout
Seven Hills is located in Ohio, United States within 41° 22' 49.08" N -82° 19' 35.04" W (41.3803, -81.6736) coordinates. The local time in Seven Hills is 03:30 (06.06.2025)
Kalmthout is located in Arr. Antwerpen, Belgium within 51° 22' 59.88" N 4° 28' 0.12" E (51.3833, 4.4667) coordinates. The local time in Kalmthout is 09:30 (06.06.2025)
The calculated flying distance from Kalmthout to Kalmthout is 3,922.29 miles which is equal to 6,312.32 km.
Seven Hills, Ohio, United States
Related Distances from Seven Hills
Kalmthout, Arr. Antwerpen, Belgium