Distance from Seven Hills to Lyaskovets
The shortest distance (air line) between Seven Hills and Lyaskovets is 5,062.17 mi (8,146.77 km).
How far is Seven Hills from Lyaskovets
Seven Hills is located in Ohio, United States within 41° 22' 49.08" N -82° 19' 35.04" W (41.3803, -81.6736) coordinates. The local time in Seven Hills is 20:49 (06.04.2025)
Lyaskovets is located in Veliko Tarnovo, Bulgaria within 43° 6' 0" N 25° 43' 0.12" E (43.1000, 25.7167) coordinates. The local time in Lyaskovets is 03:49 (07.04.2025)
The calculated flying distance from Lyaskovets to Lyaskovets is 5,062.17 miles which is equal to 8,146.77 km.
Seven Hills, Ohio, United States
Related Distances from Seven Hills
Lyaskovets, Veliko Tarnovo, Bulgaria