Distance from Seven Hills to Novy Jicin
The shortest distance (air line) between Seven Hills and Novy Jicin is 4,495.67 mi (7,235.08 km).
How far is Seven Hills from Novy Jicin
Seven Hills is located in Ohio, United States within 41° 22' 49.08" N -82° 19' 35.04" W (41.3803, -81.6736) coordinates. The local time in Seven Hills is 19:22 (15.04.2025)
Novy Jicin is located in Moravskoslezský kraj, Czechia within 49° 35' 39.84" N 18° 0' 37.08" E (49.5944, 18.0103) coordinates. The local time in Novy Jicin is 01:22 (16.04.2025)
The calculated flying distance from Novy Jicin to Novy Jicin is 4,495.67 miles which is equal to 7,235.08 km.
Seven Hills, Ohio, United States
Related Distances from Seven Hills
Novy Jicin, Moravskoslezský kraj, Czechia