Distance from Seven Hills to Oud-Turnhout
The shortest distance (air line) between Seven Hills and Oud-Turnhout is 3,944.28 mi (6,347.71 km).
How far is Seven Hills from Oud-Turnhout
Seven Hills is located in Ohio, United States within 41° 22' 49.08" N -82° 19' 35.04" W (41.3803, -81.6736) coordinates. The local time in Seven Hills is 04:34 (05.04.2025)
Oud-Turnhout is located in Arr. Turnhout, Belgium within 51° 19' 0.12" N 4° 58' 59.88" E (51.3167, 4.9833) coordinates. The local time in Oud-Turnhout is 10:34 (05.04.2025)
The calculated flying distance from Oud-Turnhout to Oud-Turnhout is 3,944.28 miles which is equal to 6,347.71 km.
Seven Hills, Ohio, United States
Related Distances from Seven Hills
Oud-Turnhout, Arr. Turnhout, Belgium