Distance from Seven Hills to Scherpenheuvel
The shortest distance (air line) between Seven Hills and Scherpenheuvel is 3,953.46 mi (6,362.48 km).
How far is Seven Hills from Scherpenheuvel
Seven Hills is located in Ohio, United States within 41° 22' 49.08" N -82° 19' 35.04" W (41.3803, -81.6736) coordinates. The local time in Seven Hills is 15:43 (05.04.2025)
Scherpenheuvel is located in Arr. Leuven, Belgium within 51° 0' 37.08" N 4° 58' 22.08" E (51.0103, 4.9728) coordinates. The local time in Scherpenheuvel is 21:43 (05.04.2025)
The calculated flying distance from Scherpenheuvel to Scherpenheuvel is 3,953.46 miles which is equal to 6,362.48 km.
Seven Hills, Ohio, United States
Related Distances from Seven Hills
Scherpenheuvel, Arr. Leuven, Belgium