Distance from Seven Hills to Sint-Kruis
The shortest distance (air line) between Seven Hills and Sint-Kruis is 3,880.35 mi (6,244.82 km).
How far is Seven Hills from Sint-Kruis
Seven Hills is located in Ohio, United States within 41° 22' 49.08" N -82° 19' 35.04" W (41.3803, -81.6736) coordinates. The local time in Seven Hills is 13:39 (05.04.2025)
Sint-Kruis is located in Arr. Brugge, Belgium within 51° 12' 42.12" N 3° 15' 0" E (51.2117, 3.2500) coordinates. The local time in Sint-Kruis is 19:39 (05.04.2025)
The calculated flying distance from Sint-Kruis to Sint-Kruis is 3,880.35 miles which is equal to 6,244.82 km.
Seven Hills, Ohio, United States
Related Distances from Seven Hills
Sint-Kruis, Arr. Brugge, Belgium