Distance from Seven Hills to Steenokkerzeel
The shortest distance (air line) between Seven Hills and Steenokkerzeel is 3,938.29 mi (6,338.07 km).
How far is Seven Hills from Steenokkerzeel
Seven Hills is located in Ohio, United States within 41° 22' 49.08" N -82° 19' 35.04" W (41.3803, -81.6736) coordinates. The local time in Seven Hills is 13:46 (05.04.2025)
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 19:46 (05.04.2025)
The calculated flying distance from Steenokkerzeel to Steenokkerzeel is 3,938.29 miles which is equal to 6,338.07 km.
Seven Hills, Ohio, United States
Related Distances from Seven Hills
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium