Distance from Sever do Vouga to Aleksandrow Lodzki
The shortest distance (air line) between Sever do Vouga and Aleksandrow Lodzki is 1,513.85 mi (2,436.31 km).
How far is Sever do Vouga from Aleksandrow Lodzki
Sever do Vouga is located in Região de Aveiro, Portugal within 40° 43' 59.88" N -9° 37' 59.88" W (40.7333, -8.3667) coordinates. The local time in Sever do Vouga is 08:33 (07.02.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 09:33 (07.02.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 1,513.85 miles which is equal to 2,436.31 km.
Sever do Vouga, Região de Aveiro, Portugal
Related Distances from Sever do Vouga
Aleksandrow Lodzki, Łódzki, Poland