Distance from Sever do Vouga to Johnstown
The shortest distance (air line) between Sever do Vouga and Johnstown is 3,598.09 mi (5,790.57 km).
How far is Sever do Vouga from Johnstown
Sever do Vouga is located in Região de Aveiro, Portugal within 40° 43' 59.88" N -9° 37' 59.88" W (40.7333, -8.3667) coordinates. The local time in Sever do Vouga is 11:50 (17.12.2025)
Johnstown is located in Pennsylvania, United States within 40° 19' 33.6" N -79° 4' 50.16" W (40.3260, -78.9194) coordinates. The local time in Johnstown is 06:50 (17.12.2025)
The calculated flying distance from Johnstown to Johnstown is 3,598.09 miles which is equal to 5,790.57 km.
Sever do Vouga, Região de Aveiro, Portugal
Related Distances from Sever do Vouga
Johnstown, Pennsylvania, United States