Distance from Severn to Argenteuil
The shortest distance (air line) between Severn and Argenteuil is 3,799.78 mi (6,115.16 km).
How far is Severn from Argenteuil
Severn is located in Maryland, United States within 39° 8' 7.8" N -77° 18' 15.84" W (39.1355, -76.6956) coordinates. The local time in Severn is 12:49 (27.02.2025)
Argenteuil is located in Val-d’Oise, France within 48° 57' 0" N 2° 15' 0" E (48.9500, 2.2500) coordinates. The local time in Argenteuil is 18:49 (27.02.2025)
The calculated flying distance from Argenteuil to Argenteuil is 3,799.78 miles which is equal to 6,115.16 km.
Severn, Maryland, United States
Related Distances from Severn
Argenteuil, Val-d’Oise, France