Distance from Severn to Aubergenville
The shortest distance (air line) between Severn and Aubergenville is 3,782.90 mi (6,087.99 km).
How far is Severn from Aubergenville
Severn is located in Maryland, United States within 39° 8' 7.8" N -77° 18' 15.84" W (39.1355, -76.6956) coordinates. The local time in Severn is 12:19 (27.02.2025)
Aubergenville is located in Yvelines, France within 48° 57' 29.88" N 1° 51' 18" E (48.9583, 1.8550) coordinates. The local time in Aubergenville is 18:19 (27.02.2025)
The calculated flying distance from Aubergenville to Aubergenville is 3,782.90 miles which is equal to 6,087.99 km.
Severn, Maryland, United States
Related Distances from Severn
Aubergenville, Yvelines, France