Distance from Severn to Bad Waldsee
The shortest distance (air line) between Severn and Bad Waldsee is 4,142.55 mi (6,666.78 km).
How far is Severn from Bad Waldsee
Severn is located in Maryland, United States within 39° 8' 7.8" N -77° 18' 15.84" W (39.1355, -76.6956) coordinates. The local time in Severn is 14:05 (04.05.2025)
Bad Waldsee is located in Ravensburg, Germany within 47° 55' 15.96" N 9° 45' 6.84" E (47.9211, 9.7519) coordinates. The local time in Bad Waldsee is 20:05 (04.05.2025)
The calculated flying distance from Bad Waldsee to Bad Waldsee is 4,142.55 miles which is equal to 6,666.78 km.
Severn, Maryland, United States
Related Distances from Severn
Bad Waldsee, Ravensburg, Germany