Distance from Severn to Begijnendijk
The shortest distance (air line) between Severn and Begijnendijk is 3,851.42 mi (6,198.27 km).
How far is Severn from Begijnendijk
Severn is located in Maryland, United States within 39° 8' 7.8" N -77° 18' 15.84" W (39.1355, -76.6956) coordinates. The local time in Severn is 10:21 (26.04.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 16:21 (26.04.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 3,851.42 miles which is equal to 6,198.27 km.
Severn, Maryland, United States
Related Distances from Severn
Begijnendijk, Arr. Leuven, Belgium