Distance from Severn to Buggenhout
The shortest distance (air line) between Severn and Buggenhout is 3,828.27 mi (6,161.00 km).
How far is Severn from Buggenhout
Severn is located in Maryland, United States within 39° 8' 7.8" N -77° 18' 15.84" W (39.1355, -76.6956) coordinates. The local time in Severn is 15:37 (22.04.2025)
Buggenhout is located in Arr. Dendermonde, Belgium within 51° 0' 0" N 4° 12' 0" E (51.0000, 4.2000) coordinates. The local time in Buggenhout is 21:37 (22.04.2025)
The calculated flying distance from Buggenhout to Buggenhout is 3,828.27 miles which is equal to 6,161.00 km.
Severn, Maryland, United States
Related Distances from Severn
Buggenhout, Arr. Dendermonde, Belgium