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      Distance from Severn to Chateauneuf-les-Martigues

      The shortest distance (air line) between Severn and Chateauneuf-les-Martigues is 4,084.31 mi (6,573.07 km).

      How far is Severn from Chateauneuf-les-Martigues

      Severn is located in Maryland, United States within 39° 8' 7.8" N -77° 18' 15.84" W (39.1355, -76.6956) coordinates. The local time in Severn is 04:50 (28.02.2025)

      Chateauneuf-les-Martigues is located in Bouches-du-Rhône, France within 43° 22' 59.16" N 5° 9' 51.12" E (43.3831, 5.1642) coordinates. The local time in Chateauneuf-les-Martigues is 10:50 (28.02.2025)

      The calculated flying distance from Chateauneuf-les-Martigues to Chateauneuf-les-Martigues is 4,084.31 miles which is equal to 6,573.07 km.

      Severn, Maryland, United States

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      Chateauneuf-les-Martigues, Bouches-du-Rhône, France

      Related Distances to Chateauneuf-les-Martigues