Distance from Severn to Koekelberg
The shortest distance (air line) between Severn and Koekelberg is 3,837.05 mi (6,175.14 km).
How far is Severn from Koekelberg
Severn is located in Maryland, United States within 39° 8' 7.8" N -77° 18' 15.84" W (39.1355, -76.6956) coordinates. The local time in Severn is 05:22 (25.02.2025)
Koekelberg is located in Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium within 50° 52' 0.12" N 4° 19' 59.88" E (50.8667, 4.3333) coordinates. The local time in Koekelberg is 11:22 (25.02.2025)
The calculated flying distance from Koekelberg to Koekelberg is 3,837.05 miles which is equal to 6,175.14 km.
Severn, Maryland, United States
Related Distances from Severn
Koekelberg, Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium