Distance from Severn to Sveti Ivan Zelina
The shortest distance (air line) between Severn and Sveti Ivan Zelina is 4,476.01 mi (7,203.43 km).
How far is Severn from Sveti Ivan Zelina
Severn is located in Maryland, United States within 39° 8' 7.8" N -77° 18' 15.84" W (39.1355, -76.6956) coordinates. The local time in Severn is 05:08 (26.02.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 11:08 (26.02.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 4,476.01 miles which is equal to 7,203.43 km.
Severn, Maryland, United States
Related Distances from Severn
Sveti Ivan Zelina, Zagrebačka županija, Croatia