Distance from Severn to Vetraz-Monthoux
The shortest distance (air line) between Severn and Vetraz-Monthoux is 4,047.68 mi (6,514.12 km).
How far is Severn from Vetraz-Monthoux
Severn is located in Maryland, United States within 39° 8' 7.8" N -77° 18' 15.84" W (39.1355, -76.6956) coordinates. The local time in Severn is 01:53 (04.05.2025)
Vetraz-Monthoux is located in Haute-Savoie, France within 46° 10' 27.12" N 6° 15' 18" E (46.1742, 6.2550) coordinates. The local time in Vetraz-Monthoux is 07:53 (04.05.2025)
The calculated flying distance from Vetraz-Monthoux to Vetraz-Monthoux is 4,047.68 miles which is equal to 6,514.12 km.
Severn, Maryland, United States
Related Distances from Severn
Vetraz-Monthoux, Haute-Savoie, France