Distance from Severna Park to Amberieu-en-Bugey
The shortest distance (air line) between Severna Park and Amberieu-en-Bugey is 4,011.68 mi (6,456.17 km).
How far is Severna Park from Amberieu-en-Bugey
Severna Park is located in Maryland, United States within 39° 5' 13.2" N -77° 25' 52.68" W (39.0870, -76.5687) coordinates. The local time in Severna Park is 00:33 (27.02.2025)
Amberieu-en-Bugey is located in Ain, France within 45° 57' 29.16" N 5° 21' 28.08" E (45.9581, 5.3578) coordinates. The local time in Amberieu-en-Bugey is 06:33 (27.02.2025)
The calculated flying distance from Amberieu-en-Bugey to Amberieu-en-Bugey is 4,011.68 miles which is equal to 6,456.17 km.
Severna Park, Maryland, United States
Related Distances from Severna Park
Amberieu-en-Bugey, Ain, France