Distance from Severna Park to Sveti Ivan Zelina
The shortest distance (air line) between Severna Park and Sveti Ivan Zelina is 4,472.93 mi (7,198.49 km).
How far is Severna Park from Sveti Ivan Zelina
Severna Park is located in Maryland, United States within 39° 5' 13.2" N -77° 25' 52.68" W (39.0870, -76.5687) coordinates. The local time in Severna Park is 17:51 (25.02.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 23:51 (25.02.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 4,472.93 miles which is equal to 7,198.49 km.
Severna Park, Maryland, United States
Related Distances from Severna Park
Sveti Ivan Zelina, Zagrebačka županija, Croatia