Distance from Sevierville to Bad Sassendorf
The shortest distance (air line) between Sevierville and Bad Sassendorf is 4,396.92 mi (7,076.16 km).
How far is Sevierville from Bad Sassendorf
Sevierville is located in Tennessee, United States within 35° 53' 13.92" N -84° 25' 55.92" W (35.8872, -83.5678) coordinates. The local time in Sevierville is 17:36 (06.03.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 23:36 (06.03.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 4,396.92 miles which is equal to 7,076.16 km.
Sevierville, Tennessee, United States
Related Distances from Sevierville
Bad Sassendorf, Soest, Germany