Distance from Sevierville to Boortmeerbeek
The shortest distance (air line) between Sevierville and Boortmeerbeek is 4,272.20 mi (6,875.45 km).
How far is Sevierville from Boortmeerbeek
Sevierville is located in Tennessee, United States within 35° 53' 13.92" N -84° 25' 55.92" W (35.8872, -83.5678) coordinates. The local time in Sevierville is 10:25 (26.02.2025)
Boortmeerbeek is located in Arr. Leuven, Belgium within 50° 58' 59.88" N 4° 34' 0.12" E (50.9833, 4.5667) coordinates. The local time in Boortmeerbeek is 16:25 (26.02.2025)
The calculated flying distance from Boortmeerbeek to Boortmeerbeek is 4,272.20 miles which is equal to 6,875.45 km.
Sevierville, Tennessee, United States
Related Distances from Sevierville
Boortmeerbeek, Arr. Leuven, Belgium