Distance from Seymour to Aartselaar
The shortest distance (air line) between Seymour and Aartselaar is 4,204.30 mi (6,766.17 km).
How far is Seymour from Aartselaar
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 17:16 (24.02.2025)
Aartselaar is located in Arr. Antwerpen, Belgium within 51° 7' 59.88" N 4° 22' 59.88" E (51.1333, 4.3833) coordinates. The local time in Aartselaar is 23:16 (24.02.2025)
The calculated flying distance from Aartselaar to Aartselaar is 4,204.30 miles which is equal to 6,766.17 km.
Seymour, Indiana, United States
Related Distances from Seymour
Aartselaar, Arr. Antwerpen, Belgium