Distance from Seymour to Alexandria
The shortest distance (air line) between Seymour and Alexandria is 5,284.27 mi (8,504.20 km).
How far is Seymour from Alexandria
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 02:44 (11.01.2026)
Alexandria is located in Teleorman, Romania within 43° 58' 6.96" N 25° 19' 59.88" E (43.9686, 25.3333) coordinates. The local time in Alexandria is 09:44 (11.01.2026)
The calculated flying distance from Alexandria to Alexandria is 5,284.27 miles which is equal to 8,504.20 km.
Seymour, Indiana, United States
Related Distances from Seymour
Alexandria, Teleorman, Romania