Distance from Seymour to Assebroek
The shortest distance (air line) between Seymour and Assebroek is 4,158.37 mi (6,692.24 km).
How far is Seymour from Assebroek
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 21:18 (24.02.2025)
Assebroek is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 15' 0" E (51.2000, 3.2500) coordinates. The local time in Assebroek is 03:18 (25.02.2025)
The calculated flying distance from Assebroek to Assebroek is 4,158.37 miles which is equal to 6,692.24 km.
Seymour, Indiana, United States
Related Distances from Seymour
Assebroek, Arr. Brugge, Belgium