Distance from Seymour to Bad Waldsee
The shortest distance (air line) between Seymour and Bad Waldsee is 4,522.89 mi (7,278.88 km).
How far is Seymour from Bad Waldsee
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 07:25 (04.03.2025)
Bad Waldsee is located in Ravensburg, Germany within 47° 55' 15.96" N 9° 45' 6.84" E (47.9211, 9.7519) coordinates. The local time in Bad Waldsee is 13:25 (04.03.2025)
The calculated flying distance from Bad Waldsee to Bad Waldsee is 4,522.89 miles which is equal to 7,278.88 km.
Seymour, Indiana, United States
Related Distances from Seymour
Bad Waldsee, Ravensburg, Germany