Distance from Seymour to Begijnendijk
The shortest distance (air line) between Seymour and Begijnendijk is 4,223.44 mi (6,796.96 km).
How far is Seymour from Begijnendijk
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 20:17 (25.04.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 02:17 (26.04.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 4,223.44 miles which is equal to 6,796.96 km.
Seymour, Indiana, United States
Related Distances from Seymour
Begijnendijk, Arr. Leuven, Belgium