Distance from Seymour to Boguszow-Gorce
The shortest distance (air line) between Seymour and Boguszow-Gorce is 4,658.71 mi (7,497.46 km).
How far is Seymour from Boguszow-Gorce
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 06:01 (10.01.2026)
Boguszow-Gorce is located in Wałbrzyski, Poland within 50° 46' 0.12" N 16° 11' 60" E (50.7667, 16.2000) coordinates. The local time in Boguszow-Gorce is 12:01 (10.01.2026)
The calculated flying distance from Boguszow-Gorce to Boguszow-Gorce is 4,658.71 miles which is equal to 7,497.46 km.
Seymour, Indiana, United States
Related Distances from Seymour
Boguszow-Gorce, Wałbrzyski, Poland