Distance from Seymour to Boortmeerbeek
The shortest distance (air line) between Seymour and Boortmeerbeek is 4,216.12 mi (6,785.19 km).
How far is Seymour from Boortmeerbeek
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 18:25 (25.04.2025)
Boortmeerbeek is located in Arr. Leuven, Belgium within 50° 58' 59.88" N 4° 34' 0.12" E (50.9833, 4.5667) coordinates. The local time in Boortmeerbeek is 00:25 (26.04.2025)
The calculated flying distance from Boortmeerbeek to Boortmeerbeek is 4,216.12 miles which is equal to 6,785.19 km.
Seymour, Indiana, United States
Related Distances from Seymour
Boortmeerbeek, Arr. Leuven, Belgium