Distance from Seymour to Borgerhout
The shortest distance (air line) between Seymour and Borgerhout is 4,204.05 mi (6,765.77 km).
How far is Seymour from Borgerhout
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 18:17 (25.04.2025)
Borgerhout is located in Arr. Antwerpen, Belgium within 51° 12' 42.12" N 4° 26' 26.52" E (51.2117, 4.4407) coordinates. The local time in Borgerhout is 00:17 (26.04.2025)
The calculated flying distance from Borgerhout to Borgerhout is 4,204.05 miles which is equal to 6,765.77 km.
Seymour, Indiana, United States
Related Distances from Seymour
Borgerhout, Arr. Antwerpen, Belgium